Optimal. Leaf size=136 \[ \frac{a \text{PolyLog}\left (2,-\frac{a+b x+1}{-a-b x+1}\right )}{b^2}-\frac{\left (a^2+1\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}+\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}+\frac{2 a \log \left (\frac{2}{-a-b x+1}\right ) \tanh ^{-1}(a+b x)}{b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2 \]
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Rubi [A] time = 0.200218, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1., Rules used = {6111, 5928, 5910, 260, 6048, 5948, 5984, 5918, 2402, 2315} \[ \frac{a \text{PolyLog}\left (2,-\frac{a+b x+1}{-a-b x+1}\right )}{b^2}-\frac{\left (a^2+1\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}+\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}+\frac{2 a \log \left (\frac{2}{-a-b x+1}\right ) \tanh ^{-1}(a+b x)}{b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2 \]
Antiderivative was successfully verified.
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Rule 6111
Rule 5928
Rule 5910
Rule 260
Rule 6048
Rule 5948
Rule 5984
Rule 5918
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int x \tanh ^{-1}(a+b x)^2 \, dx &=\frac{\operatorname{Subst}\left (\int \left (-\frac{a}{b}+\frac{x}{b}\right ) \tanh ^{-1}(x)^2 \, dx,x,a+b x\right )}{b}\\ &=\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2-\operatorname{Subst}\left (\int \left (-\frac{\tanh ^{-1}(x)}{b^2}+\frac{\left (1+a^2-2 a x\right ) \tanh ^{-1}(x)}{b^2 \left (1-x^2\right )}\right ) \, dx,x,a+b x\right )\\ &=\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{\operatorname{Subst}\left (\int \tanh ^{-1}(x) \, dx,x,a+b x\right )}{b^2}-\frac{\operatorname{Subst}\left (\int \frac{\left (1+a^2-2 a x\right ) \tanh ^{-1}(x)}{1-x^2} \, dx,x,a+b x\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2-\frac{\operatorname{Subst}\left (\int \frac{x}{1-x^2} \, dx,x,a+b x\right )}{b^2}-\frac{\operatorname{Subst}\left (\int \left (\frac{\left (1+a^2\right ) \tanh ^{-1}(x)}{1-x^2}-\frac{2 a x \tanh ^{-1}(x)}{1-x^2}\right ) \, dx,x,a+b x\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}+\frac{(2 a) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}(x)}{1-x^2} \, dx,x,a+b x\right )}{b^2}-\frac{\left (1+a^2\right ) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}(x)}{1-x^2} \, dx,x,a+b x\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}-\frac{\left (1+a^2\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}+\frac{(2 a) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}(x)}{1-x} \, dx,x,a+b x\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}-\frac{\left (1+a^2\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{2 a \tanh ^{-1}(a+b x) \log \left (\frac{2}{1-a-b x}\right )}{b^2}+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}-\frac{(2 a) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-x}\right )}{1-x^2} \, dx,x,a+b x\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}-\frac{\left (1+a^2\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{2 a \tanh ^{-1}(a+b x) \log \left (\frac{2}{1-a-b x}\right )}{b^2}+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}+\frac{(2 a) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-a-b x}\right )}{b^2}\\ &=\frac{(a+b x) \tanh ^{-1}(a+b x)}{b^2}-\frac{a \tanh ^{-1}(a+b x)^2}{b^2}-\frac{\left (1+a^2\right ) \tanh ^{-1}(a+b x)^2}{2 b^2}+\frac{1}{2} x^2 \tanh ^{-1}(a+b x)^2+\frac{2 a \tanh ^{-1}(a+b x) \log \left (\frac{2}{1-a-b x}\right )}{b^2}+\frac{\log \left (1-(a+b x)^2\right )}{2 b^2}+\frac{a \text{Li}_2\left (1-\frac{2}{1-a-b x}\right )}{b^2}\\ \end{align*}
Mathematica [A] time = 0.265043, size = 98, normalized size = 0.72 \[ \frac{-2 a \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(a+b x)}\right )+\left (-a^2+2 a+b^2 x^2-1\right ) \tanh ^{-1}(a+b x)^2-2 \log \left (\frac{1}{\sqrt{1-(a+b x)^2}}\right )+2 \tanh ^{-1}(a+b x) \left (2 a \log \left (e^{-2 \tanh ^{-1}(a+b x)}+1\right )+a+b x\right )}{2 b^2} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.052, size = 365, normalized size = 2.7 \begin{align*}{\frac{{x}^{2} \left ({\it Artanh} \left ( bx+a \right ) \right ) ^{2}}{2}}-{\frac{ \left ({\it Artanh} \left ( bx+a \right ) \right ) ^{2}{a}^{2}}{2\,{b}^{2}}}+{\frac{{\it Artanh} \left ( bx+a \right ) x}{b}}+{\frac{{\it Artanh} \left ( bx+a \right ) a}{{b}^{2}}}-{\frac{{\it Artanh} \left ( bx+a \right ) \ln \left ( bx+a-1 \right ) a}{{b}^{2}}}+{\frac{{\it Artanh} \left ( bx+a \right ) \ln \left ( bx+a-1 \right ) }{2\,{b}^{2}}}-{\frac{{\it Artanh} \left ( bx+a \right ) \ln \left ( bx+a+1 \right ) a}{{b}^{2}}}-{\frac{{\it Artanh} \left ( bx+a \right ) \ln \left ( bx+a+1 \right ) }{2\,{b}^{2}}}+{\frac{\ln \left ( bx+a-1 \right ) }{2\,{b}^{2}}}+{\frac{\ln \left ( bx+a+1 \right ) }{2\,{b}^{2}}}-{\frac{ \left ( \ln \left ( bx+a-1 \right ) \right ) ^{2}a}{4\,{b}^{2}}}+{\frac{a}{{b}^{2}}{\it dilog} \left ({\frac{1}{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) }+{\frac{\ln \left ( bx+a-1 \right ) a}{2\,{b}^{2}}\ln \left ({\frac{1}{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) }+{\frac{ \left ( \ln \left ( bx+a-1 \right ) \right ) ^{2}}{8\,{b}^{2}}}-{\frac{\ln \left ( bx+a-1 \right ) }{4\,{b}^{2}}\ln \left ({\frac{1}{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) }-{\frac{\ln \left ( bx+a+1 \right ) a}{2\,{b}^{2}}\ln \left ( -{\frac{bx}{2}}-{\frac{a}{2}}+{\frac{1}{2}} \right ) }+{\frac{a}{2\,{b}^{2}}\ln \left ({\frac{1}{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) \ln \left ( -{\frac{bx}{2}}-{\frac{a}{2}}+{\frac{1}{2}} \right ) }+{\frac{ \left ( \ln \left ( bx+a+1 \right ) \right ) ^{2}a}{4\,{b}^{2}}}-{\frac{\ln \left ( bx+a+1 \right ) }{4\,{b}^{2}}\ln \left ( -{\frac{bx}{2}}-{\frac{a}{2}}+{\frac{1}{2}} \right ) }+{\frac{1}{4\,{b}^{2}}\ln \left ({\frac{1}{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) \ln \left ( -{\frac{bx}{2}}-{\frac{a}{2}}+{\frac{1}{2}} \right ) }+{\frac{ \left ( \ln \left ( bx+a+1 \right ) \right ) ^{2}}{8\,{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.987025, size = 273, normalized size = 2.01 \begin{align*} \frac{1}{2} \, x^{2} \operatorname{artanh}\left (b x + a\right )^{2} + \frac{1}{8} \, b^{2}{\left (\frac{8 \,{\left (\log \left (b x + a - 1\right ) \log \left (\frac{1}{2} \, b x + \frac{1}{2} \, a + \frac{1}{2}\right ) +{\rm Li}_2\left (-\frac{1}{2} \, b x - \frac{1}{2} \, a + \frac{1}{2}\right )\right )} a}{b^{4}} + \frac{4 \,{\left (a + 1\right )} \log \left (b x + a + 1\right )}{b^{4}} + \frac{{\left (a^{2} + 2 \, a + 1\right )} \log \left (b x + a + 1\right )^{2} - 2 \,{\left (a^{2} + 2 \, a + 1\right )} \log \left (b x + a + 1\right ) \log \left (b x + a - 1\right ) +{\left (a^{2} - 2 \, a + 1\right )} \log \left (b x + a - 1\right )^{2} - 4 \,{\left (a - 1\right )} \log \left (b x + a - 1\right )}{b^{4}}\right )} + \frac{1}{2} \, b{\left (\frac{2 \, x}{b^{2}} - \frac{{\left (a^{2} + 2 \, a + 1\right )} \log \left (b x + a + 1\right )}{b^{3}} + \frac{{\left (a^{2} - 2 \, a + 1\right )} \log \left (b x + a - 1\right )}{b^{3}}\right )} \operatorname{artanh}\left (b x + a\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x \operatorname{artanh}\left (b x + a\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \operatorname{atanh}^{2}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \operatorname{artanh}\left (b x + a\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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